Comparison tests

Level UniversityDifficulty ★★★★★Concept⌖ Open in the map

What is it?

For positive terms: if ak≤bka_k \le b_k and ∑bk\sum b_k converges, so does ∑ak\sum a_k. The limit version: if ak/bk→c∈(0,∞)a_k / b_k \to c \in (0, \infty), both series behave the same. In practice, compare with geometric or pp-series.

Formulas

0≤ak≤bk, ∑bk<∞  ⟹  ∑ak<∞0 \le a_k \le b_k,\ \sum b_k < \infty \implies \sum a_k < \infty
akbk→c∈(0,∞)  ⟹  (∑ak<∞  ⟺  ∑bk<∞)\frac{a_k}{b_k} \to c \in (0,\infty) \implies \Big(\sum a_k < \infty \iff \sum b_k < \infty\Big)

Where it shows up in computing

  • Algorithm analysis and complexity★★★★★frequentScientific computing and algorithms

    Bounding a messy cost sum by a simpler one is exactly how asymptotic bounds are proved.

Where is it used?

Computing topics reachable from here, through the chain of ideas that leads to them:

What depends on it

This page has the essentials. A fuller treatment (intuition, formal definition, worked example) is on the way.

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