Weierstrass extreme value theorem

Level UniversityDifficulty ★★★★★Theorem⌖ Open in the map

What is it?

A continuous function on a closed bounded interval attains a maximum and a minimum. Without it, "find the best solution" might have no answer.

Statement

f∈C[a,b]  ⟹  ∃xm,xM∈[a,b]: f(xm)≤f(x)≤f(xM) ∀x∈[a,b]f \in C[a,b] \implies \exists x_m, x_M \in [a,b]:\ f(x_m) \le f(x) \le f(x_M)\ \forall x \in [a,b].

Idea of the proof

Take xnx_n with f(xn)→sup⁡ff(x_n) \to \sup f; Bolzano–Weierstrass gives a convergent subsequence xnk→cx_{n_k} \to c, and continuity gives f(c)=sup⁡ff(c) = \sup f.

Where it shows up in computing

  • Operations research and logistics★★★★★advancedOptimization and systems

    Existence of an optimal solution: a continuous cost on a compact feasible set always has a minimum.

Where is it used?

Computing topics reachable from here, through the chain of ideas that leads to them:

What depends on it

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