Root test

Level UniversityDifficulty ★★★★★Concept⌖ Open in the map

What is it?

If lim sup⁡∣ak∣1/k=L\limsup |a_k|^{1/k} = L: L<1L < 1 converges, L>1L > 1 diverges. Slightly stronger than the ratio test; it gives the radius of convergence of power series (Cauchy–Hadamard).

Formulas

lim sup⁡k→∞∣ak∣1/k<1  ⟹  ∑∣ak∣<∞\limsup_{k\to\infty}|a_k|^{1/k} < 1 \implies \sum |a_k| < \infty

What depends on it

This page has the essentials. A fuller treatment (intuition, formal definition, worked example) is on the way.

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